Jawapan Buku Teks Fizik Tingkatan 4 Kssm: Aktiviti 13 Work Work

W = F × s = 50 N × 2 m = 100 J

Solution:

KE = ½ × m × v^2 = ½ × 2 kg × (4 m/s)^2 = 16 J

GPE = m × g × h

A machine requires an input energy of 2000 J to lift a 50 kg load to a height of 2 m. If the machine takes 5 seconds to lift the load, calculate its efficiency.

A 5 kg object is moving at a velocity of 2 m/s. Calculate its kinetic energy.

Work is defined as the product of the force applied to an object and the displacement of the object in the direction of the force. Mathematically, work (W) is represented by the equation: W = F × s = 50 N

Work done = m × g × h = 100 kg × 9.8 m/s^2 × 5 m = 4900 J

Solution:

A 20 N force is applied to a block, causing it to move 3 m to the right. Calculate the work done on the block. Calculate its kinetic energy

Work done = m × g × h = 50 kg × 9.8 m/s^2 × 2 m = 980 J

Kinetic energy is the energy of motion. An object possesses kinetic energy when it is moving. The kinetic energy (KE) of an object is given by the equation:

In this guide, we will explore the concept of work, energy, and efficiency in the context of physics. Specifically, we will focus on Aktiviti 13 in the Buku Teks Fizik Tingkatan 4 KSSM (Kurikulum Standard Sekolah Menengah) textbook. This activity aims to help students understand the relationship between force, displacement, and work done, as well as the concepts of kinetic energy, potential energy, and efficiency. Calculate the work done on the block

In this guide, we've explored the concepts of work, energy, and efficiency in the context of physics. We've also applied these concepts to Aktiviti 13 in the Buku Teks Fizik Tingkatan 4 KSSM. By understanding these concepts, students can develop a deeper appreciation for the relationships between force, displacement, energy, and efficiency.

KE = ½ × m × v^2