Using Newton's second law: F - f = ma 10 - f = 2(3) f = 4 N
A 5 kg block is lifted vertically upwards from the ground to a height of 10 m. Find the gain in potential energy.
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Using the equation: ΔU = mgh ΔU = 5(10)(10) = 500 J
v'₂ = 2v₁ / (m₁ + m₂) v'₂ = 2(5) / (2 + 3) = 2 m/s Using Newton's second law: F - f =
A 2 kg ball collides elastically with a 3 kg ball at rest. The initial velocity of the 2 kg ball is 5 m/s. Find the final velocities of both balls.
A block of mass 2 kg is placed on a horizontal surface. A force of 10 N is applied to the block, causing it to accelerate at 3 m/s². Find the coefficient of friction. The initial velocity of the 2 kg ball is 5 m/s
Using the equation: f = μN 4 = μ(2)(10) μ = 0.2